"> Word Problem 9 | Job Exam Rare Mathematics (JEMrare)

Word Problem 9

Problem 9: A sold a table to B at 4% profit.B sold the same table for Rs 65, thereby he made a profit of 25%. Find the price at which A had purchased the table.

a.  40             b.60.          c.50                   d.70

Solution:

Let the cost price for A is Rs ‘y’. A earns a profit of 4% of his cost price

i-e

A's Profit=\frac{4}{100} of 'y'

=\frac{4y}{100}

=\frac{y}{25}

But

Profit= Sale Price - Cost Price

\Rightarrow \frac{y}{25} = SP-y

\Rightarrow SP=\frac{y}{25}+y

=\frac{26y}{25}

So, the sale price at which A sold table to B is 26y/25. So, now it will stand as cost price for B.

Now we consider B’s case

Cost price of B

CP=\frac{26y}{25}

Sale price by B at which he sold table is Rs. 65 i-e

SP=65

Profit earned by B is 25% of his cost price i-e

P=\frac{25}{100} of CP

=\frac{1}{4} \times \frac{26y}{25}

But

Profit=Sale Price-Cost Price

or

P=SP-CP

Putting values of P, SP, CP

\Rightarrow\frac{1}{4}\times\frac{26y}{25}=65-\frac{26y}{25}

\Rightarrow\frac{1}{4} \times \frac{26y}{25}+\frac{26y}{25}=65

\Rightarrow\frac{5}{4} \times \frac{26y}{25}=65

\Rightarrow y=\frac{4}{5} \times \frac{25}{26}\times65

\Rightarrow y=50

So the cost price by A was Rs 25

(GRE arithmetic questions and answers, css screening test math)

Share this:

Leave a Reply

Your email address will not be published.

You may use these <abbr title="HyperText Markup Language">HTML</abbr> tags and attributes: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <s> <strike> <strong>

Facebook
Twitter