Word Problem 2

Problem 2: If 3 men or 6 boys can do a piece of work in 20 days, then in how many days 6 men and 8 boys will finish the same work?

how to turn an equation into a word problem, word problems with answers, algebra word problems, word problems high school



Solution:

First Case (work is done by 3 men or 6 boys)

or

3M=6B

\Rightarrow 1M = \frac{6}{3}B

\Rightarrow 1M = 2B----(1)

2nd Case (work is done by 6 men and 8 boys)

or

6M+8B

Putt value of M from eq(1)

\Rightarrow 6M+8B=6\left ( 2B \right )+8B=12B+8B=20B

So, 6 men and 8 boys are equal to 20 boys;

Now if 1st case is taken with boys only, then 6 boys do the work in 20 days. In 2nd case now all men and boys are equal to 20 boys, so we can suppose that 20 boys can do the work in ‘x’ days.

We arrange data as below;

Solving for x;

\frac{x}{20}=\frac{6}{20}

\Rightarrow x = \frac{6\times 20}{20}

\Rightarrow x = 6

 So, 20 boys will finish the same work in 6 days

Insert math as
Block
Inline
Additional settings
Formula color
Text color
#333333
Type math using LaTeX
Preview
\({}\)
Nothing to preview
Insert
Share