"> Word Problem 19 | Job Exam Rare Mathematics (JEMrare)

Word Problem 19

Problem 19: A boy buys an article at 75% of its value and sells it for 20% more than its value. His percent profit based on cost will be;

a. 50%           b.60%           c. 70%          d. 75%

— Value math —

Solution:

Let value of the article is ‘y’ Rs. He buys it at 75% of its value i-e;

CP=\frac{75}{100}Of y

or

CP=\frac{75}{100}y

He sells it at 20% more of its initial value i-e;

 SP=\frac{20}{100}y+y

Now using profit formula

P=SP-CP

P=\frac{20}{100}y+y-\frac{75}{100}y

\Rightarrow P=y-\frac{55}{100}y

\Rightarrow P=\frac{45}{100}y

So profit is 45% of CP

To find %age of profit on CP we use %age formula;

Profit%age= \frac{Profit}{Cost}\times 100

\Rightarrow Profit%age= \frac{45}{75}\times 100

\Rightarrow Profit%age=60%

 

 

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