d Word Problem 10 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

Word Problem 10

Problem 10: Find a number which after being multiplied by 5 will exceed 60 as much as it is now short of 60.

a. 10 b. 15 c. 25. d.20

— number math —

Solution:

Let the number is ‘y’ and if we add ‘z’ it will become equal to 60 (we supposing it is ‘z’ less than 60)

i-e we suppose;

$z+y=60$

$\Rightarrow z=60-y ---(1)$

Now five time of the number;

$=5y$

Five times of number exceeds 60 by ‘z’

$5y=60+z$

$z=5y-60-----(2)$

Com pairing eq 1 & 2

$\Rightarrow 5y-60=60-y$

$\Rightarrow 6y=120$

$\Rightarrow y=20$

So, the number is 20

Check

Number =20

Short of 60=60-20 = 40

i-e it is 40 less than 60

Now five times of number = 5×20=100

Excess more than 60 =100-60=40

Thus it is 40 more than 60 and meets the condition of the problem

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Word Problem 10

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