d Word Problem 5 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

Word Problem 5

Problem 5: Divide Rs 420 among A, B and C so that A may receive 1/2 as much as B and C together and 2/3 of what A and C together receive.

a) 140, 168, 112                         b) 150, 158, 112                          c) 140, 170, 110                 d) 240, 68, 112



1st Condition:

A receives half of what B and C get together;


A =\frac{1}{2}(B+C)

2nd Condition:

B receives two third of  what A and C get together;

B =\frac{2}{3}(A+C)


From 1st condition we can say;


\Rightarrow A : (B+C)=1:2

Sum Of Ratios = 1+2=3

Using share formula;

A's Share = \frac{Total Amount}{Sum Of ratios}\times A's Ratio

A's Share = \frac{420}{3}\times 1

\Rightarrow A's Share = 140

From 2nd condition we can say;


Sum Of Ratios=2+3=5

B's Share=\frac{Total Amount}{Sum Of Ratios}\times B's Ratio

 \Rightarrow B's Share=\frac{420}{5}\times 2

 \Rightarrow B's Share= 168

As the amount of Rs 420 is being divided among A, B and C, So, sum of their shares should be equal to 420!

\Rightarrow A+B+C=420 ----(1)

Put values of A’s share and B’s share in eq(1)

\Rightarrow 140+168+C=420

\Rightarrow C=420 -140-168

\Rightarrow C=112

So, the correct option is ‘c’


You may submit a MCQ or maths problem with solution tips here in the comment box below! If you could not solve anyone, you may submit a MCQ or maths problem without solution as well. We will try our level best to solve it for you!

Your email address will not be published.

You may use these <abbr title="HyperText Markup Language">HTML</abbr> tags and attributes: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <s> <strike> <strong>