d Word Problem 4 (Share calculation as per condition) | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

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Word Problem 4 (Share calculation as per condition)

Share Calculation 0

Problem 4: Divide Rs 5625 among A, B and C so that A may receive 1/2 as much as B and C together, and B 1/4th of what A and C together receive.

a) 1125, 1875, 2630 b) 1875, 1125, 2625 c) 2625, 1875, 1125 d) none

Solution:

(general math for jobs)

Here,

1st Condition:

A receives half of what B and C get together;

i-e

$A = \frac{1}{2}(B+C)$

2nd Condition

B receives one fourth of what A and C receive together;

i-e

$B = \frac{1}{4}(A+C)$

———————————————————————–

From 1st condition we can write;

$\frac{A}{B+C}=\frac{1}{2}$

$\Rightarrow A : (B+C)=1:2$

$\Rightarrow Sum Of Ratios=1+2=3$

Using share formula;

$A's Share=\frac{Total Amount}{Sum Of Ratio}\times A's Ratio$

$\Rightarrow A's Share=\frac{5625}{3}\times 1$

$\Rightarrow A's Share= 1875$

In the same way from 2nd condition we can write;

$\frac{B}{A+C}=\frac{1}{4}$

$\Rightarrow B: (A+C)=1:4$

$\Rightarrow Sum Of Ratios=1+4=5$

Using formula of share calculation;

$B's Share=\frac{Total Amount}{Sum Of Ratio}\times B's Ratio$

$B's Share=\frac{5625}{5}\times 1$

$B's Share=1125$

Also we know that total amount is being divided among A, B and C, so sum of their shares should be 5625!

$\Rightarrow A+B+C = 5625 ----(1)$

Put values of A’s share and B’s share in eq (1)

$\Rightarrow 1875+1125+C = 5625$

$\Rightarrow C=5625-1875-1125=2625$

So, we have calculated shares of A,B and C

So option ‘b’ is the answer

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