d Word Problem 6 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

# Word Problem 6

Problem 6: Divide Rs 290 among A, B and C persons, so that 1/2 of A’s share may be equal to 2/3 of B’s share, and 2/3 of B’s share may be equal to 1/4 of C’s share.

 (adsbygoogle = window.adsbygoogle || []).push({}); 

Solution:

Amount to be divided = 290 Rs

1st-Condition of division – half of A’s share should be equale to two third of B’s share;

2nd-Condition of division – two third of B’s share should be equale to one fourth of C’s share;

Also the amount divided to A,B and C should be 290 in total;

From 1st condition we can write;

From 2nd condition we can write;

Put values of A and C from eqs  2 & 3 in eq 1;

Put this value of B in eq 2 and eq 3

and

•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•