Question 53 & 54
This is a Situation of direct proportion i-e as the days increase, more cats require more mice and few cats will require few mice.
Formula here is ;
So, 4 cats will also require 100 days to eat 4 mice !
Here the technique of distance formula is to be used. Distance is calculated by multiplying speed with time taken. Here we have to calculate the distance.
Let the total distance is ‘x’ Kms from point A to C!
Let distance covered from point A to B in first half i-e in 5 hours is X kms and distance covered from B to C in second half i-e next 5 hours is Y kms
Case 1 – Distance for First Half (5 hours) :
We are given that in first half he travels with speed of 21 kms per hour.
We know Distance = Speed x Time
S is distance, V is speed and T is time; Put values of S, V and T in the relation, we get;
S= X, V=21 km/h and T=5 hours
Case 2 – Distance For second half ( Next 5 hours):
We use same formula. Here Time is again 5 hours, but for second half speed will be 24 kms per hour.
S= Y, V=24 km/h and T=5 hours
So, total distance is X+Y i-e 105+120 = 225 kms