Word Problem 5_

Profit & Loss 0

Problem 5: A dealer sales a shirt and gets a profit of 15%. Had he sold it for Rs 4 more, he would have earned profit of 5% more. What is the cost price of the shirt?

Solution:

Let CP of Shirt =x

Profit =P= 15% of x

So it means by formula;

$SP = P+CP$

$SP = 15% of x + x$

$\Rightarrow SP= \frac{15}{100}x+x$

$\Rightarrow SP= \frac{15x+100x}{100}$

$\Rightarrow SP= \frac{115x}{100}$

Now according to condition – if he had sold it for 4 Rs more, i-e with $SP= \frac{115x}{100}+4$ , he would earn profit of 20% ( 4% more than earlier!)

So, in this case;

CP=x

$SP= \frac{115x}{100x}+4$

P= 20 % of x

Again using formula for profit

$P= SP-CP$

$P=( \frac{115x}{100}+4)-x$

$\Rightarrow P=( \frac{115x+400-100x}{100})$

$\Rightarrow P=( \frac{15x+400}{100})$

Taking 100 to LHS

$\Rightarrow 100 \times P=15x+400$

Now ,

$P= \frac{20}{100}x$

put in above;

$\Rightarrow 100 \times \frac{20}{100}x =15x+400$

$\Rightarrow 20x =15x+400$

$\Rightarrow 20x -15x=400$

$\Rightarrow 5x=400$

$\Rightarrow x=\frac{400}{5}$

$\Rightarrow x=80 Rs$

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Word Problem 5_

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Word Problem 5_

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