Word Problem 13 ( Gain or loss percentage calculation)
Problem 13: A man buys a certain number of oranges at 24 a rupee and an equal number at 30 a rupee. He mixes these at 27 a rupee. What does he gain or loss percent?
a. 1-19/81% b. 1-5/7% c. 5-1/2% d. 5-1/3%
GRE arithmetic questions and answers
Suppose the man buys ‘y’ number each rated type of oranges
then for 24 a rupee oranges we can write;
Similarly for 30 a rupee oranges we write;
So, cost prices for y oranges of 24 a rupee type and y oranges of 30 a rupee type are y/24 and y/30 rupees respectively.
Now total cost price for both type of oranges is;
Now the man mixes both types oranges which become 2y in number. He sells these at 27 a rupee rate.
for sale price of 2y oranges at this rate we can write;
so mixed oranges sale price is
Here we can see now that CP is greater than SP i-e total cost price for individual type is greater than sale price for mixed oranges. It means he is earning no profit but a loss !
formula for loss is
Now formula for loss %age is
Putting values of loss L and cost CP from above
After simplification we get;
So, the option ‘a’ is correct answer
‘css screening test math’
basic arithmetic mcqs, pakmcqs maths, asan mcqs,word problems with answers, word problems algebra, math word problems worksheets, word problems pdf, math word problems 5th grade, math word problems solver,