d Word Problem 3 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

# Word Problem 3

Problem 3: In an examination a candidate who secures 25% of the maximum marks fails by 60 marks. Another candidate who secures 42 % of the total marks gets 8 marks more than necessary for passing. Find the maximum marks and the percentage for passing.

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(word problems on job exam mathematics.)

Solution:

Let  the maximum marks =’x’

And let there be two candidates ‘A’ and ‘B’

Let pass marks = y% of x

We consider ‘A’s case

Candidate ‘A’

‘A’ gets 25% marks of total marks and fails by 60 marks. It means had had’A’ got 60 more marks he would has passed the exam ! i-e 25%+60 marks would have made him successful.

so we say mathematically,

Eq (1) and (2) both are expressing pass marks , so both should be equal!

Now we consider ‘B’s case

Candidate ‘B’

“B’ gets 42% marks of total marks ‘x’ which are 8 marks more than needed to pass, i-e if 8 marks were deducted from his score than remaining marks would be equal to passing marks!

We write mathematically;

Now eq (1) and (4) both express passing marks, so should be equal!

Subtracting eq(3) and (5) from both sides;

So, total marks were 400

Put this value of x in eq (3) or (5) {we putting in eq 3}

So, passing marks were 40%

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