d Word Problem 8 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

# Word Problem 8

Problem 8: A reduction of 20% in the price of sugar enables a purchaser to buy 4 kgs more for Rs 80. The original price of 1 kg of sugar was;

a) Rs 4                          b) Rs 4.50                   c) Rs 8                         d) Rs 5.50

(word problems on job exam mathematics.)

Solution:

We suppose;

Original price of sugar per kg It means y rupees is equal to 1 kg of sugar i-e Now we calculated quantity of sugar in 80 Rs according to original price, so, from above we get; Multiply both sides by 80 Now we come to new price per kg,  after reduction of 20 % in original price. i-e after reduction of per kg. But new price per kg is calculated by subtracting reduction from original price i-e;

New Price   This simply means now 1 kg of sugar can be bought in Rs .  We can write;   Now we will calculate quantity of sugar in 80 Rs according to New Price ( After Reduction);, So multiply both sides by 80;  But according to condition of question, this quantity of sugar in Rs 80 as per new price should be 4 kg more than quantity of sugar in 80 Rs as per original price ! i-e we will add 4 kg more to , then both quantities of Rs 80 will be equal!

i-e Shift ‘y’ terms to one side;    So original price of sugar per kg was Rs 5

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