d Word Problem 13 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

Word Problem 13

Problem 13: A man spends 12-1/2% of his money and after spending 75% of the remainder, he had Rs 175 left.The money he had at first was;

a. Rs 2000                   b. Rs 1750             c. Rs 700                  d, Rs 800

Percentage calculation –

pre employment exam questions, basic math test with answers, mathematical test, numerical logic test


Let the man has amount of ‘y’ Rs in the beginning;

First spending is 12-1/2% or 12.5% of ‘y’ Rs !

i-e          First Spending = \frac{12.5}{100}y

Remaining amount will be calculated by subtracting this spent amount from the original amount !


Remaining Amount = y-\frac{12.5}{100}y

\Rightarrow Remaining Amount = \frac{87.5}{100}y

Second spending is 75% of this remaining amount ;

 so, \Rightarrow Second Spending = \frac{75}{100} (\frac{87.5}{100}y)

\Rightarrow Second Spending = \frac{6562.5}{10000} y

Now in the end the remaining amount is to be calculated by subtracting second spending from first remaining amount;


\Rightarrow Second Remaining Amount = \frac{87.5}{100} y-\frac{6562.5}{10000} y

hence, \Rightarrow Second Remaining Amount = \frac{2187.5}{10000} y

But second remaining amount is given to be Rs 175

\Rightarrow 175 = \frac{2187.5}{10000} y

\Rightarrow y= \frac{1750000}{2187.5}

\Rightarrow y= 800

So, the he had Rs 800 in his hands before spending




Digiprove sealCopyright secured by Digiprove © 2021

You may submit a MCQ or maths problem with solution tips here in the comment box below! If you could not solve anyone, you may submit a MCQ or maths problem without solution as well. We will try our level best to solve it for you!

Your email address will not be published.

You may use these <abbr title="HyperText Markup Language">HTML</abbr> tags and attributes: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <s> <strike> <strong>