Question 25 & 26
Cricket fans know there are 6 balls in one over. So, in 10 overs there will be 10×6=60 balls !
Run rate of 3.2 means a score of 3.2 runs in one over – so,
So, it means out of target of 282 runs , 32 runs have readily been scored in first 10 overs. Now match is of 50 overs, so question is 282-32=250 runs will be scored with what run rate in next 40 overs !
Or simply we can say that next 40 overs should give 250 runs i-e;
So, a required run rate is of 6.25 runs in next 40 overs !
Here,
Rate of interest =R= 5% pa
Term of Calculation of interest = T = 1/2
(One year is taken as one term and half yearly calculations will be 1/2 terms two times in one year)
Principal or initial amount of investment =P= 1600 Rs
We know the formula of Compound Interest calculation;
Put values from given data;
Or (rounding off)
Now we also know ;
Where,
A = final amount including interest
I = Interest amount
P= Principal amount
So, we have;
So amount for first half term is Rs 40/-
Now for next half term of the same year A will become principal amount;
So data for next half term can be arranged as;
P = 1640
R = 5% pa
T = 1/2
Again applying;
Or ( rounding off)
So, real interest on Rs 1600/- till end of second half becomes Rs 81
So total Internet = interest in first half + new interest till end of second half
Interest = 40+81=121
Jalal
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Anonymous
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