d Question 1 & 2 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

Question 1 & 2

Question 1: In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was

a 2700, b 2900, c 3000 ( Assistant Director IB FPSC 2018)


This is simply a percentage calculation problem;

Total votes =7500 (given)

Total invalid votes = 20% of total votes

\Rightarrow Invalid Votes=20% of 7500

Invalid Votes = \frac{20}{100}\times 7500=1500

So Valid votes = 7500-1500=600

First Candidate

First candidate get 55% of total valid votes

\Rightarrow Votes First Candidate=55% of 6000

=\frac{55}{100}\times 6000=3300

Second Candidate

Votes by second candidate =Total Valid Votes – Votes by First Candidate =6000-3300=2700

So the option ‘a’ is the answer

(math portion of job test)

Question 2: A man took loan from a bank at the rate of 12% p.a. Simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was?

a 5000,b 15000,c 12000 ( Assistant Director IB FPSC 2018)


This is problem of simple interest.

We are given;

Rate of interest (R) = 12 pa

Term of Loan investment (T) = 3 yrs

Interest incurred (I) = 5400

Amount borrowed or Principal Amount (P)=?

We know the simple interest formula;

I=\frac{P\times R\times T}{100}

Putting given values

5400=\frac{P\times 12\times 3}{100}

\Rightarrow P= \frac{5400\times100 }{12\times 3}

\Rightarrow P= \frac{540000 }{36}=15000

So, the principal amount (borrowed amount was Rs 15000

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