d maths to solve - base 2 number

# Question 10 (Addition of numbers with base 2)

Question 10 : Find the sum of ​$$(111)_2 and (10)_2$$​.

a ​$$(1001)_2$$​               b) $$(1011)_2$$​             c) $$(1101)_2$$​                  d) $$(1111)_2$$

Solution:

In maths to solve it, first of all we arrange these numbers in column and row style;

Here we start by adding entries in right column, then we will add entries in center column and lastly we will deal with left column entry which is 1 here.

We see that numbers are with base 2 !

To take sum of entries in each column , we will assume here that 2 is equal to 10 – i-e whenever we move two counts ahead we will assume it as 10.

To understand it  we see that;

1- In right side column there are entries 1 and 0 . Taking sum i-e 1+0 = 1  which we write below line.

$\begin{equation} \frac{ \begin{array}[b]{r} \left( 111 \right)_2\\ \ + \left( 10 \right)_2 \end{array} }{ \left( 1 \right) } \end{equation}$

2- In the center column there are entries 1 and 1 . Taking sum 1+1 = 2, but as said above we assume that 2 is equal to 10 ! So, 1+1=10 . The we write 0 below line –  and carry 1 on last or left column

$\begin{equation} \frac{ \begin{array}[b]{r} \left( 111 \right)_2\\ \ + \left( 10 \right) \end{array} }{ \left( 01 \right) } \end{equation}$

3- In the left coloumn there is only one entry i-e 1. We add this one with the carried 1 and again we get 1+1=2 but 2 is assumed to be equal to 10 so 1+1=10 which we write below line as below;

$\begin{equation} \frac{ \begin{array}[b]{r} \left( 111 \right)_2\\ \ + \left( 10 \right)_2 \end{array} }{ \left( 1001 \right)_2 } \end{equation}$

Note:  Ignore ‘[b] r’ written up on left !

So,in  maths to solve this question , option a is correct one here !

•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•