Word Problem

Career test math Problems

Problem : A reduction of 20 percent in the price of tea enables a purchaser to obtain 4 kg more for Rs 80. The reduced price per kg of tea is ;

a. Rs 4 b. Rs 3 c. Rs 7 d. Rs 8

Finite math, business math –

Solution:

Let the original price be Rs ‘y’ per kg

20 percent of this price;

i-e

$20percent Of y'= \frac{20}{100}y$

$\Rightarrow 20percent Of y'= \frac{y}{5}$

So new price per kg can be calculated by subtracting this 20% of y – from original price ‘y’

i-e

$New Price = Original Price - 20% of Original Price$

$\Rightarrow New Price = y - \frac{y}{5}$

$\Rightarrow New Price = \frac{4y}{5}$

Now According to statement of question – purchaser gets 4 kg more – if Rs 80 given more!

i-e For new price he gets 1 kg (because this is the new price per kg) – and if he gives Rs 80 more he will get 4 kg more i-e 1+4=5 kg he will get !

i-e $New Price Per KG+Rs 80 = 1Kg +4 kg$

$\Rightarrow \frac{4y}{5}+80=1+4$

$\Rightarrow \frac{4y}{5}+80=5$

$\Rightarrow 4y+400=25$

$\Rightarrow 4y=375$

$\Rightarrow y=\frac{375}{4}$

Put this value of ‘y’ in New Price above

i-e $New Price=\frac{4y}{5}$

$New Price=\frac{4\times (375/4)}{5}$

$New Price=\frac{375}{5}$

$New Price=75$

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