d – Job Exam Rare Mathematics (JEMrare) - Solved MCQs | Job Exam Rare Mathematics (JEMrare) - Solved MCQs
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imageLet Reaction force be =N

Let angle at which road is banked = \theta



Ncosθ = mg (horizontal component of N is balancing weight of the car) –1(1)

and

Nsinθ = mv2/r (Vertical component of N is balancing centrifugal force on the car)–(2)

Dividing eq 2 by eq 1 we get

tanθ = v2/(gr)

= \frac{25.9^{2}}{9.8\times 118.0}

\vartheta = tan ^{-1}(0.566724317)

\vartheta = 0.5156

 

 

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