d Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers. | Job Exam Rare Mathematics (JEMrare) - Solved MCQs
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Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers.

Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers.

Solution: 

Let the numbers are ‘x’ and ‘z’.

Let  ‘x’ be 40% more than ‘y’,

then

\[ x= \frac{40}{100}y+y=\frac{2}{5}y+y=\frac{7y}{5} \]

And let ‘z’ is 60% more than ‘y’

then

\[ z= \frac{60}{100}y+y=\frac{3}{5}y+y=\frac{8y}{5} \]

Now the ratio

\[ x:z=\frac{7y}{5}:\frac{8y}{5}=7:8 \]

 

So, the ratio is 7:8 or 8:7

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