d Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers. | Job Exam Rare Mathematics (JEMrare) - Solved MCQs

# Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers.

Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers.

Solution:

Let the numbers are ‘x’ and ‘z’.

Let  ‘x’ be 40% more than ‘y’,

then

$x= \frac{40}{100}y+y=\frac{2}{5}y+y=\frac{7y}{5}$

And let ‘z’ is 60% more than ‘y’

then

$z= \frac{60}{100}y+y=\frac{3}{5}y+y=\frac{8y}{5}$

Now the ratio

$x:z=\frac{7y}{5}:\frac{8y}{5}=7:8$

So, the ratio is 7:8 or 8:7