Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers.
Problem: Two numbers are 40.%and 60% more than a number ‘y’. Find the ratio of the first two numbers.
Solution:
Let the numbers are ‘x’ and ‘z’.
Let ‘x’ be 40% more than ‘y’,
then
\[ x= \frac{40}{100}y+y=\frac{2}{5}y+y=\frac{7y}{5} \]
And let ‘z’ is 60% more than ‘y’
then
\[ z= \frac{60}{100}y+y=\frac{3}{5}y+y=\frac{8y}{5} \]
Now the ratio
\[ x:z=\frac{7y}{5}:\frac{8y}{5}=7:8 \]
So, the ratio is 7:8 or 8:7