d Question 3: Factorize ( x + y) 2 -14z( x + y) + 49z 2 | Job Exam Rare Mathematics (JEMrare) - Solved MCQs
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Question 3: Factorize ( x + y) 2 -14z( x + y) + 49z 2

4. a 2 ± 2ab + b 2 type expressions 0

Question 3: Factorize  (x+y)^{2}-14z(x+y)+ 49z^{2}

Factorizing an expression —

Solution:

 

 

Given expression is

(x+y)^{2}-14z(x+y)+ 49z^{2}

We convert this expression into (a)^{2}-2(a)(b)+ (b)^{2}= (a-b)^{2} form!

= (x+y)^{2}-2(x+y)(7z)+ (7z)^{2}

= [(x+y)-(7z)]^{2}

== [x+y-7z]^{2}

 

This so because here as per formula;

x+y = a

and

z=b

and

[(x+y)-(7z)]=a-b

 

 


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